WebIf the sum of the first m terms of an AP be n and the sum of its first n terms be m then show that the sum of its first term is − (m + n). Q. If in an AP the sum of first m terms= n and the sum of first n terms= m, prove that sum of (m+n) term is -(m+n). WebSolution Verified by Toppr Let a be the first term and d be the common difference of the given A.P. Then, S m=n 2m{2a+(m−1)d}=n 2am+m(m−1)d=2n ... (i) and, S n=m 2n{2a+(n−1)d} 2an+n(n−1)d=2m ... (ii) Subtracting equation (ii) from equation (i), we get 2a(m−n)+{m(m−1)−n(n−1)}d=2n−2m 2a(m−n)+{(m 2−n 2)−(m−n)}d=−2(m−n)

If in an A.P. the sum of m terms is equal to n and the sum of n …

WebIn an AP if Sm=Sn and also m>n then find the value of S(m-n)First term = a , common difference = d Sm = n →m/2(2a + (m-1)d) = n …….(1) Sn = m × Book a Trial With Our Experts csgo command bot

Partial sums: formula for nth term from partial sum

WebIf in an AP the sum of m terms is equal to n end the sum of n terms is equal to m then prove that the sum of (m + n) terms is - (m+n) Solution First term = a , common difference = d … WebSep 7, 2024 · If in an A.P., Sn = qn^2 and Sm = qm^2, where Sr denotes the sum of r terms of the A.P., then Sq equals - Sarthaks eConnect Largest Online Education Community If in an A.P., Sn = qn^2 and Sm = qm^2, where Sr denotes the sum of r terms of the A.P., then Sq equals ← Prev Question Next Question → 0 votes 1.3k views WebOct 10, 2016 · Males were more represented in the AP group than the AN group (48% and 42% respectively, p=0.039; Table 3). The median BMI were 28.9 kg/m 2 and 28.5 kg/m 2 for AN and AP respectively (p=0.9). Overweight/obesity had higher frequency in adenoma group (81% of AP patients had BMI more than 25 kg/m 2 compared to 75% in AN patients, … e4 weakness\u0027s