Web⇒(a−b) 2+(b−c) 2+(a−c) 2=0 Since, all the three terms in the above addition are positive which cannot be summed up to zero. Therefore, (a−b)=(b−c)=(c−a)=0 ⇒a=b=c Thus, A=B=C=60 o=sin 2A+sin 2B+sin 2C=3× 43= 49 Video Explanation Solve any question of Determinants with:- Patterns of problems > Was this answer helpful? 0 0 Similar questions WebFeb 10, 2024 · In any triangle ABC, prove that sin2A + sin2B – sin2C = 4cosA cosBsinC. class-12 Share It On Facebook Twitter 1 Answer +1 vote answered Feb 10, 2024 by Beepin …

Prove that $\\sin(2A)+\\sin(2B)+\\sin(2C)=4\\sin(A)\\sin(B)\\sin(C

WebIn a triangle, with using notation a2b2c2 (sin2A + sin2B + sin2C) = 3 where is the area of the triangle then the value of is (A) 1/4 (B) 1 (C) 8 (D*) 32 2 8 3 [Hint: ab = etc. a b c = 2 2 2 sin C sin A sin B sin C 8 3 and sin 2 A = 4sinAsinBsinC · 4sinAsinBsinC = … WebIn ΔABC, if sin2A + sin2B + sin2C = 2, then the triangle isIn triangle ABC, if sin^2A+sin^2B=sin^2C, then the triangle isin a Δ ABC , if sin^2 A + sin^2 B + ... In ΔABC, if sin2A + sin2B +... chinatown new year celebration

In ΔABC, A + B + C = π show that sin2A + sin2B − sin2C = 2 sin A …

Weba2b2c2 (sin2A + sin2B + sin2C) = 3 where is the area of the triangle then the value of is (A) 1/4 (B) 1 (C) 8 (D) 32. Q16. The general value of x satisfying the ... Similar Triangles + Identity. Similar Triangles + Identity. AceZeta. Student Book Trigonometry. Student Book Trigonometry. Azizah Noor. Algebra 1 Unit 5. Algebra 1 Unit 5. WebThis shows that, one of the angles A, B or C must be 90 degrees. π π π π ⇒ sin 2 A = sin 2 π 2 = 1 ⇒ sin 2 B + sin 2 C = sin 2 π 2 – C + sin 2 C = cos 2 C + sin 2 C = 1 ∴ sin 2 A + sin 2 B … WebSolution We know that, sin 2 θ = 1 - cos 2 θ 2 L.H.S. = sin 2 A + sin 2 B + sin 2 C = A B C 1 - cos 2 A 2 + 1 - cos 2 B 2 - sin 2 C = A B C 1 2 [ 2 - ( cos 2 A + cos 2 B)] - sin 2 C = A B A B C … chinatown new year parade 2023